4.9x^2-18x-70=0

Solution for 4.9x^2-18x-70=0 equation:

4.9x^2-18x-70=0

a = 4.9; b = -18; c = -70;
Δ = b2-4ac
Δ = -182-4·4.9·(-70)
Δ = 1696
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1696}=\sqrt{16*106}=\sqrt{16}*\sqrt{106}=4\sqrt{106}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-18)-4\sqrt{106}}{2*4.9}=\frac{18-4\sqrt{106}}{9.8}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-18)+4\sqrt{106}}{2*4.9}=\frac{18+4\sqrt{106}}{9.8}
$